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महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

In the Given Figure, a Toy Made from a Hemisphere, a Cylinder and a Cone Are Shown. Find the Total Area of the Toy. - Geometry Mathematics 2

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प्रश्न

In the given figure, a toy made from a hemisphere, a cylinder and a cone are shown. Find the total area of the toy.

बेरीज
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उत्तर

Radius of the sphere = Radius of the cylinder = Radius of cone = r = 3 cm
Height of the cone, h = 4 cm
Height of the cylinder, H = 40 cm 
Let the slant height of the cone be l cm.

l2 = r2 + h2

= 32 +42

= 9 + 16

= 25

l = `sqrt25`

∴ l = 5 cm

Total area of the toy = Curved surface area of hemisphere + Curved surface area of cylinder + Curved surface area of cone

\[= 2\pi r^2 + 2 \pi rH + \pi rl\]
\[ = 2\pi \times \left( 3 \right)^2 + 2\pi \times 3 \times 40 + \pi \times 3 \times 5\]
= 2π × 9 + 240π + 15π

= 18π + 240π + 15π

= 273π cm2

Thus, the total area of the toy is 273π cm2.

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पाठ 7: Mensuration - Practice set 7.1 [पृष्ठ १४५]

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बालभारती Mathematics 2 [English] Standard 10 Maharashtra State Board
पाठ 7 Mensuration
Practice set 7.1 | Q 8 | पृष्ठ १४५
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