Question

In the given circle with diameter AB, find the value of x.

Answer 1

∠ABD = ∠ACD = 30°   ...[Angle in the same segment]

Now in ΔADB,

∠BAD + ∠ADB + ∠ABD = 180°  ...[Angles of a triangle]

But, ∠ADB = 90°  ...[Angle in a semi-circle]

∴ x + 90° + 30° = 180°

`=>` x + 120° = 180°

`=>` x = 180° – 120°

`=>` x = 60°