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प्रश्न
In the following triangle, find the value of x
बेरीज
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उत्तर
Let ∠J = x and ∠L = 3x
By angle sum property of triangle we have
∠J + ∠K + ∠L = 180°
x + 112° + 3x = 180°
4x = 180° – 112°
x = 68°
x = `(68^circ)/4`
x = 17°
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पाठ 4: Geometry - Exercise 4.1 [पृष्ठ ७३]
