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प्रश्न
In the following radioactive equation,
\[\ce{^235_92U -> X + α -> Y + β -> Z + γ}\]
The atomic numbers of nuclei X, Y and Z are:
पर्याय
ZX = 90, ZY = 91, ZZ = 91
ZX = 88, ZY = 89, ZZ = 89
ZX = 90, ZY = 91, ZZ = 91
ZX = 92, ZY = 91, ZZ = 91
MCQ
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उत्तर
ZX = 90, ZY = 91, ZZ = 91
Explanation:
α-decay drops the atomic number from 92 to 90, β-decay increases it by one to 91, and γ-decay keeps it unchanged at 91.
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पाठ 12: Modern Physics - Intex Question [पृष्ठ २९३]
