Advertisements
Advertisements
प्रश्न
In the figure, O is the centre of the circle and the length of arc AB is twice the length of arc BC. If angle AOB = 108°, find: ∠CAB
बेरीज
Advertisements
उत्तर
Join AD and DB
Arc B = 2 arc BC and ∠AOB = 180°
∴ ∠BOC = `1/2` ∠AOB
= `1/2 xx 108^circ`
= 54°
Now, Arc BC subtends ∠BOC at the centre and ∠CAB at the remaining part of the circle.
∴ ∠CAB = `1/2` ∠BOC
= `1/2 xx 54^circ`
= 27°
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
