Question

In the figure given above, ‘O’ is the centre of the circle, seg PS is a tangent segment and S is the point of contact. Line PR is a secant.
If PQ = 3.6, QR = 6.4, find PS.

Solution:

PS² = PQ × `square` ......(tangent secant segments theorem)

= PQ × (PQ + `square`)

= 3.6 × (3.6 + 6.4)

= 3.6 × `square`

= 36

∴ PS = `square` .....(by taking square roots)

Answer 1

PS² = PQ × PR ......(tangent secant segments theorem)

= PQ × (PQ + QR)

= 3.6 × (3.6 + 6.4)

= 3.6 × 10

= 36

∴ PS = 6 .....(by taking square roots)