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प्रश्न
In the adjoining diagram, G is the centroid of ΔABC. A(3, –3), В(2, –6), C(x, y) and G(5, –5). The coordinates of point D are:

पर्याय
(2, –6)
(3, –6)
(6, –6)
(10, –6)
MCQ
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उत्तर
(6, –6)
Explanation:
The centroid G has coordinates equal to the average of the vertices.
So, `((3 + 2 + x)/3, (-3 + (-6) + y)/3) = (5, −5)`.
Solving gives x = 10 and y = –6.
Point D is the midpoint of BC.
So, D = `((2 + 10)/2, (-6 + (-6))/2) = (6, -6)`.
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