Question

In a solid the energy level is lying 0.012 eV below Fermi level. What is the probability of this level not being occupied by an electron 27℃?

Answer 1

:-Data  :- -E_F E=0.012eV  ,T=27℃=300K

`K=1.38×10^(-23) J/K= =(1.38×10^(-23))/(1.6×10^(-19 ))=86.25×10^-6  eV/K `

Formula :-f(E_c)=  `1/(1+e("^(E_c- E_F))/(kT )`
Calculations:-Total probability = 1

Probability of occupying an energy state + Probability of not occupying the energy state = 1. f(E) + Probability of not occupying the energy state = 1 Probability of not occupying the energy state = 1- f(E)

`"Here" f(E) =1/(1+e((E-E_f))/(kT )) =1/(1+e^((0.012/86.25×10^-6×300))) = 0.386`

Hence ,1-f(E)=1-0.386=0.614

Answer:-Probability of not occupying=0.614