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प्रश्न
In the given figure, ∠CAB = 90° and AD⊥BC. Show that ΔBDA ~ ΔBAC. If AC = 75cm, AB = 1m and BC = 1.25m, find AD.
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उत्तर
In Δ BDA and Δ BAC, we have :
∠𝐵𝐷𝐴= ∠𝐵𝐴𝐶=90°
∠𝐷𝐵𝐴= ∠𝐶𝐵𝐴 (𝐶𝑜𝑚𝑚𝑜𝑛)
Therefore, by AA similarity theorem, Δ BDA - Δ BAC
⇒ `(AD)/(AC)=(AB)/(BC)`
`⇒(AD)/0.75=1/1.25`
`⇒ AD=0.75/1.25`
= 0.6 m or 60 cm
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