Question

In the following figure, shows a kite in which BCD is the shape of a quadrant of a circle of radius 42 cm. ABCD is a square and Δ CEF is an isosceles right angled triangle whose equal sides are 6 cm long. Find the area of the shaded region.

 

Answer 1

We will find the area of the shaded region as shown below,

Area of the shaded region = area of quadrant + area of isosceles triangle ……..(1)

`∴" Area of shaded region"=90/360xxpixx42^2+1/2xx6xx6`

`∴" Area of shaded region"=1/4xxpixx42^2+1/2xx36`

Substituting  `pi=22/7` we get,

`∴ "Area of shaded region"=1/4xx22/7xx42^2+1/2xx36`

`∴ "Area of shaded region"=1/2xx11xx6xx42+18`

`∴ "Area of shaded region"=11xx3xx42+18`

`∴ "Area of shaded region"=1386+18`

`∴ "Area of shaded region"=1404` 

Therefore, area of the shaded region is `1404 cm^2`