Question

In the following figure, seg BE ⊥ seg AB and seg BA ⊥ seg AD. If BE = 6 and \[\text{AD} = 9 \text{ find} \frac{A\left( \Delta ABE \right)}{A\left( \Delta BAD \right)} \cdot\]

Answer 1

\[AD = 9 \text{ find} \frac{A\left( \Delta ABE \right)}{A\left( \Delta BAD \right)} \cdot\]

\[\frac{Ar\left( \bigtriangleup ABE \right)}{Ar\left( \bigtriangleup BAD \right)} = \frac{\frac{1}{2} \times BE \times AB}{\frac{1}{2} \times AB \times AD} = \frac{BE}{AD} = \frac{6}{9} = \frac{2}{3}\]