Question

In a family of 3 children, find the probability of having at least one boy.

Answer 1

All possible outcomes are BBB, BBG, BGB, GBB, BGG, GBG, GGB and GGG.

Number of all possible outcomes = 8

Let E be the event of having at least one boy.

Then the outcomes are BBB, BBG, BGB, GBB, BGG, GBG and GGB.

Number of possible outcomes = 7
∴ P(Having at least one boy) = P(E) =`"Number of  favourable outcomes to E"/"Number of all possible outcome"=7/8`
                                                           

Thus, the probability of having at least one boy is `7/8`