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प्रश्न
In CH4, NH3, and H2O, the central atom undergoes sp3 hybridization – yet their bond angles are different. Why?
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उत्तर
According to VSEPR theory, as H2O has two lone pairs so it repels the bond pairs much more and makes the bond angle shorter of 104.5 degrees, and as NH3 has one lone pair that repels the three bond pairs but not much effectively and strongly as two lone pairs of water repel one bond pair.
So the bond angle between the Hydrogen atom of ammonia is 107.5 greater than that of water. Similarly, methane molecules have no lone pair and bond pair repels each other with an equal bond angle between two adjacent hydrogen atoms becomes 109°.28′.
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संबंधित प्रश्न
Hybridisation of central atom in PCl5 involves the mixing of orbitals.
In which of the following molecules / ions BF3, NO2– H20 the central atom is sp2 hybridised?
Which of the following conditions is not correct for resonating structures?
Define Hybridisation.
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What type of hybridisation is possible in the following geometeries?
tetrahedral
What type of hybridisation is possible in the following geometeries?
square planer
In which of the following molecule does the central atom have two p-orbitals unused?
Which one of the following is the correct set with respect to molecule, hybridization and shape?
Which pair of species having identical shapes?
