Question

In the below given figure, a tower AB is 20 m high and BC, its shadow on the ground, is 20√3 m long. Find the sun’s altitude. 

Answer 1

LetAB be the tower and BC be its shadow.
AB = 20, BC = 20√3
In ΔABC,

`tan theta= `

`tan theta=20/(20sqrt3)`

`tan theta=1/sqrt3`

`but,tan30=1/sqrt3`

`theta=30^@`

The Sun is at an altitude of 30º .