Advertisements
Advertisements
प्रश्न
In below fig, determine the value of x.

Advertisements
उत्तर १
Since sum of all the angles round a point is equal to 360°.Therefore
⇒ 3x + 3x +150 + x = 360°
⇒ 7x° = 360° -150°
⇒ 7x = 210°
⇒ x = `210/7`
⇒ x = 30°
उत्तर २
In the given figure:

AOB is a straight line. Thus,∠AODand ∠BODform a linear pair.
Therefore their sum must be equal to180°.
We can say that
∠AOD+∠BOD = 180°
It is given that ∠AOD=150°, substituting this value in equation above, we get:
`150° + x = 180°`
` x = 180° - 150°`
` x =30°`
APPEARS IN
संबंधित प्रश्न
If an angle is 28° less than its complement, find its measure.
In the below fig, POQ is a line. Ray OR is perpendicular to line OS is another ray lying
between rays OP and OR. Prove that ∠ROS = 1 (∠QOS − ∠POS).

Define complementary angles.
Define supplementary angles.
out of \[\overleftrightarrow{AB},\overrightarrow{AB},\overleftarrow{AB}\] and `overline(AB)` which one has a fixed length?
In the following figure, ∠AOB and ∠AOC are adjacent angles? Give the reason for your answer.

In the given figure, if x = 2y, find x and y

Write the complement of (x + 5)°
In the given figure, lines PQ, MN, and RS intersect at O. If x : y = 1 : 2 and z = 90°, find ∠ROM and ∠POR.

AB, CD and EF are three lines intersecting at the same point.
(i) Find x, if y = 45° and z = 90°.
(ii) Find a, if x = 3a, y = 5x and r = 6x.

