Question

In an ideal conductor without collisions, which relation connects the change in kinetic energy to the change in potential energy?

पर्याय

• \[\Delta K = \Delta U_{\text{pot}} = -IV\Delta t\]

• \[\Delta K = \Delta U_{\text{pot}} = IV\Delta t\]

• \[\Delta K = -\Delta U_{\text{pot}} = IV\Delta t\]

• \[\Delta K = -\Delta U_{\text{pot}} = \frac{IV}{\Delta t}\]

Answer 1

With no collisions, the increase in kinetic energy equals the decrease in potential energy. Thus, \[\Delta K = -\Delta U_{\text{pot}} = IV\Delta t\].