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प्रश्न
In an ammeter, 20% of the main current passes through the galvanometer. If the resistance of the galvanometer is G, then the shunt resistance in ohms is
पर्याय
\[\frac{G}{4}\]
\[\frac{G}{8}\]
\[\frac{G}{9}\]
\[\frac{G}{10}\]
MCQ
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उत्तर
\[\frac{G}{4}\]
Explanation:
\[\mathrm{I_{g}=\frac{20}{100}}\]\[\mathrm{I}=\frac{\mathrm{I}}{5}\]
Using S = \[\frac{\mathrm{I_{g}G}}{\mathrm{I-I_{g}}}\] we get,
\[\therefore\quad\mathrm{S=~\frac{I_gG}{I-I_g}=\frac{\left(\frac{I}{5}\right)G}{\left(I-\frac{I}{5}\right)}=\frac{\left(\frac{I}{5}\right)G}{\frac{4}{5}I}=\frac{G}{4}}\]
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