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प्रश्न
In ΔABC, angle C is 90° then find the value of sin (A + B).
बेरीज
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उत्तर
Given:
Triangle ABC with angle C = 90°
Formula:
Sum of angles in a triangle is 180° and sin(90°) = 1
Solution:
A + B + C = 180° [Sum of interior angles of a triangle is 180°]
A + B + 90° = 180° [Substituting the given value of angle C]
A + B = 180° − 90° [Transposing 90° to the right side]
A + B = 90° [Subtracting 90° from 180°]
sin(A + B) = sin(90°) [Taking sine on both sides]
sin(A + B) = 1 [Using the standard trigonometric value sin(90°) = 1]
∴ sin(A + B) = 1
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