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प्रश्न
In ΔABC, ∠A = 90°. If AB = 5 units and AC = 12 units, find: sinB
बेरीज
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उत्तर
In ΔABC,
BC2 = AB2 + AC2
⇒ BC = `sqrt("AB"^2 + "AC"^2)`
⇒ BC = `sqrt(5^2 + 12^2)`
= `sqrt(169)`
= 13
AC = 12 units
BC = 13units
AB = 5units
Sin B
= `"Perpndicular"/"Hypoenuse"`
= `"AC"/"BC"`
= `(12)/(13)`
and
cos B
= `"Base"/"Hypotenuse"`
= `"AB"/"BC"`
= `(5)/(13)`.
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