Question

In a series RL circuit, V_R = 200 V and V_L = 150 V. Find the applied voltage.

पर्याय

• 350 V

• 250 V

• 500 V

• 300 V

Answer 1

250 V

Explanation:

Given: Potential drop across R = 200 V
Potential drop across L = 150 V
Now the applied voltage given is V = \[\sqrt{V_{R}^{2}+V_{L}^{2}}\]

V = \[\sqrt{\left(200\right)^2+\left(150\right)^2}\] = 250 volt