Advertisements
Advertisements
प्रश्न
In a partially destroyed laboratory record of an analysis of regression data, the following data are legible :
Variable of X = 9
Regression equations : 8x - 10g + 66 = 0 and 40x- 18g = 214
Find Mean values of X and Y on the basis of the above information .
बेरीज
Advertisements
उत्तर
Given variance of x `sigma _x^2 = 9 => sigma_x = 3`
Regression equations :
8x - 10 y + 66 = 0 ....(i)
40 x - 18 y = 214 ....(ii)
The mean values of X and Y are the point of intersection of `bar x` and `bar y`
Solving (i) and (ii)
8x- 10y = - 66 multiply by 5
`40x - 50y = - 330`
`(40 x - 18 y = 214)/(-32 y = - 544)`
`therefore "y" = 544/32 = 17`
y = 17
Substituting in (i)
8x - 170 = - 66
8x = 170 - 66
x = `104/8 = 13`
∴ x = 13
∴ Mean of x = 13 ,
mean of y = 17
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
