मराठी

In a G.P., the 4th term is 48 and 7th term is 384. Find its 6th term.

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प्रश्न

In a G.P., the 4th term is 48 and 7th term is 384. Find its 6th term.

बेरीज
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उत्तर

Let first term of G.P. be a and common ratio be r.

By formula,

⇒ an = arn − 1

Given,

4th term of G.P. = 48

⇒ a4 = 48

⇒ ar4 − 1 = 48

⇒ ar3 = 48 ..........(1)

Given,

7th term of G.P. = 384

⇒ a7 = 48

⇒ ar7 − 1 = 384

⇒ ar6 = 384 ..........(2)

Dividing equation (2) by (1), we get:

⇒ `(ar^6)/(ar^3)​ = 384/48`

⇒ r3 = 8

⇒ r3 = 23

⇒ r = 2

Substituting value of r in equation (1), we get:

⇒ a(2)3 = 48

⇒ a × 8 = 48

⇒ a = `48/8​` = 6.

⇒ a6 = ar6 − 1

⇒ a6 = ar5

⇒ a6 = 6 × 25

⇒ a6 = 6 × 32

⇒ a6 = 192.

Hence, 6th term of G.P. = 192.

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पाठ 11: Geometric Progression - TEST YOURSELF [पृष्ठ १५६]

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सेलिना Concise Mathematics [English] Class 10 ICSE
पाठ 11 Geometric Progression
TEST YOURSELF | Q 9. | पृष्ठ १५६
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