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प्रश्न
In a frequency distribution, the mid-value of a class is 12 and the class-size is 20. The lower limit of the class is ______.
पर्याय
2
8
10
12
MCQ
रिकाम्या जागा भरा
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उत्तर
In a frequency distribution, the mid-value of a class is 12 and the class-size is 20. The lower limit of the class is 2.
Explanation:
Let lower limit = L and upper limit = U.
Class-mark (mid-value) `m = (L + U)/2 = 12` and class-size h = U – L = 20.
So, U = L + 20.
Substitute:
`(L + (L + 20))/2 = 12`
⇒ `(2L + 20)/2 = 12`
⇒ L + 10 = 12
⇒ L = 2
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