Question

In a double slit experiment light has a frequency of 6 × 10¹⁴ s^-1. The distance between the centres of adjacent bright fringes is 0.75 mm."What is the distance between the slits if the screen is 1.5 m away?

पर्याय

• 10^-1 m

• 10^-3 m

• 10^-5 m

• 1 m

Answer 1

10^-3 m

Explanation:

v = 6 × 10¹⁴ s^-1

`lambda = "c"/nu = (3 xx 10^8)/(6 xx 10^14) = 5 xx 10^-7` m

β = 0.75 mm = 0.75 × 10^-3 m

D = 1.5 m

`beta = (lambda"D")/"d" = (5 xx 10^-7 xx 1.5)/(0.75 xx 10^-3)`

`beta = 10^-3`