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In a ∆ABC, prove the following, ababABABa+ba-b=tan(A+B2)cot(A-B2) - Mathematics

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प्रश्न

In a ∆ABC, prove the following, `("a"+ "b")/("a" - "b") = tan(("A" + "B")/2) cot(("A" - "B")/2)`

बेरीज
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उत्तर

We know `"a"/sin"A" = "b"/sin"B" = "c"/sin"C"` = 2R

`"a"/sin"A"` = 2R ⇒ a = 2R sin A

`"b"/sin"B"` = 2R ⇒ b = 2R sin B

`"c"/sin"C"` = 2R ⇒ c = 2R sin C

`("a" +"b")/("a" - "b") = (2"R" sin"A" + 2"R" sin"B")/(2"R" sin"A" - 2"R" sin"B")`

= `(2"R" (sin "A" + sin "B"))/(2"R" (sin"A" - sin "B"))`

= `(sin "A" + sin "B")/(sin "A" - sin "B")`

= `(2sin(("A" + "B")/2) * cos(("A" - "B")/2))/(2cos(("A" + "B")/2) * sin(("A" - "B")/2))`

= `(sin(("A" + "B")/2))/(cos(("A" + "B")/2)) xx (cos(("A" - "B")/2))/(sin(("A" - "B")/2))`

`("a"+ "b")/("a" - "b") = tan(("A" + "B")/2) * cot(("A" - "B")/2)`

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Properties of Triangle
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Trigonometry - Exercise 3.9 [पृष्ठ १४३]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
पाठ 3 Trigonometry
Exercise 3.9 | Q 7. (v) | पृष्ठ १४३

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