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महाराष्ट्र राज्य शिक्षण मंडळएचएससी वाणिज्य (इंग्रजी माध्यम) इयत्ता १२ वी

If y = xxm(x+x2-1)m, then xdydx(x2-1)dydx = ______. - Mathematics and Statistics

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प्रश्न

If y = `("x" + sqrt("x"^2 - 1))^"m"`, then `("x"^2 - 1) "dy"/"dx"` = ______.

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उत्तर

If y = `("x" + sqrt("x"^2 - 1))^"m"`, then `("x"^2 - 1) "dy"/"dx"` = my.

Explanation:

y = `("x" + sqrt("x"^2 - 1))^"m"`

Differentiating both sides w.r.t. x, we get

`"dy"/"dx" = "m" ("x" + sqrt("x"^2 - 1))^"m - 1" * "d"/"dx" ("x" + sqrt("x"^2 - 1))`

`= "m" ("x" + sqrt("x"^2 - 1))^"m"/("x" + sqrt("x"^2 - 1))^1 * [1 + 1/(2sqrt("x"^2 - 1)) * "d"/"dx" ("x"^2 - 1)]`

`= "my"/("x" + sqrt("x"^2 - 1)) xx [(1 + 1/(2sqrt("x"^2 - 1))) ("2x")]`

`= "my"/("x" + sqrt("x"^2 - 1)) xx (1 + "x"/sqrt("x"^2 - 1))`

∴ `"dy"/"dx" = "my"/("x" + sqrt("x"^2 - 1)) xx (sqrt("x"^2 - 1) + "x")/sqrt("x"^2 - 1)`

∴ `"dy"/"dx" = "my"/sqrt("x"^2 - 1)`

∴ `sqrt("x"^2 - 1) * "dy"/"dx" = "my"`

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पाठ 3: Differentiation - MISCELLANEOUS EXERCISE - 3 [पृष्ठ १००]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
पाठ 3 Differentiation
MISCELLANEOUS EXERCISE - 3 | Q II] 10) | पृष्ठ १००

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