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प्रश्न
If y = `sin^-1 (xsqrt(1 - x) + sqrt(x) sqrt(1 - x^2))`, then `("d"y)/("d"x)` = ______.
पर्याय
`(-2x)/sqrt(1 - x^2) + 1/(2sqrt(x - x^2))`
`(-1)/sqrt(1 - x^2) - 1/(2sqrt(x - x^2))`
`(-1)/sqrt(1 - x^2) + 1/(2sqrt(x - x^2))`
None of these
MCQ
रिकाम्या जागा भरा
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उत्तर
If y = `sin^-1 (xsqrt(1 - x) + sqrt(x) sqrt(1 - x^2))`, then `("d"y)/("d"x)` = `(-1)/sqrt(1 - x^2) + 1/(2sqrt(x - x^2))`.
Explanation:
Putting x = sin A and `sqrt(x)` = sin B, we get
y = `sin^-1 (sin "A"sqrt(1 - sin^2"B") + sin"B"sqrt(1 - sin^2))`
= `sin^-1 (sin "A" cos "B" + sin "B" cos "A")`
= `sin^-1 [sin("A" + "B")]`
= A + B
= `sin^-1x + sin^-1 sqrt(x)`
∴ `("d"y)/("d"x) = 1/sqrt(1 + x^2) + 1/sqrt(1 - (sqrt(x))^2) * 1/(2sqrt(x))`
= `1/sqrt(1 - x^2) + 1/(2sqrt(x - x^2)`
shaalaa.com
Derivative of Inverse Functions
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