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If xpyq = (x + y)p+q then Prove that dydx=yx - Mathematics and Statistics

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प्रश्न

If xpyq = (x + y)p+q then Prove that `dy/dx = y/x`

बेरीज
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उत्तर

xpyq = (x + y)p+q

Taking log both side

p log x + q log y = (p + q) log (x + y)

Differentiating w.r.t. x

`p/x + q/y dy/dx = (p + q)/(x + y) + ((p + q)/(x + y))dy/dx`

`q/ydy/dx - ((p + q)/(x + y)) dy/dx = (p + q)/(x + y) - p/x`

`(q/y - (p + q)/(x + y)) dy/dx = ((p + q)/(x + y) - p/x)`

`((qx - py)/y)dy/dx = ((qx - py)/x)`

`1/y dy/dx = 1/x`

`dy/dx = y/x`

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2013-2014 (March)

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