Advertisements
Advertisements
प्रश्न
If x3 + 6x2 + 4x + k is exactly divisible by x + 2, then k =
पर्याय
−6
−7
−8
−10
Advertisements
उत्तर
As f(x) = x3 + 6x2 + 4x + k is exactly divisible by (x +2).
i.e., ( x+2)is a factor of f(x).
Therefore, f(-2) =0
`(-2)^3 + 6(-2)^2 + 4(-2) + k = 0`
`-8 +24 - 8+ k = 0`
` = -8`
APPEARS IN
संबंधित प्रश्न
Write the coefficient of x2 in the following:
`9-12x +X^3`
If x = 0 and x = −1 are the roots of the polynomial f(x) =2x3 − 3x2 + ax + b, find the value of a and b.
Find the values of p and q so that x4 + px3 + 2x3 − 3x + q is divisible by (x2 − 1).
x3 − 3x2 − 9x − 5
Factorize of the following polynomials:
x3 + 13x2 + 31x − 45 given that x + 9 is a factor
If f(x) = x4 − 2x3 + 3x2 − ax − b when divided by x − 1, the remainder is 6, then find the value of a + b
If x − a is a factor of x3 −3x2a + 2a2x + b, then the value of b is
Factorise the following:
z² + 4z – 12
Factorise the following:
12x2 + 36x2y + 27y2x2
Factorise:
3x3 – x2 – 3x + 1
