Advertisements
Advertisements
प्रश्न
If x3 + 6x2 + 4x + k is exactly divisible by x + 2, then k =
पर्याय
−6
−7
−8
−10
Advertisements
उत्तर
As f(x) = x3 + 6x2 + 4x + k is exactly divisible by (x +2).
i.e., ( x+2)is a factor of f(x).
Therefore, f(-2) =0
`(-2)^3 + 6(-2)^2 + 4(-2) + k = 0`
`-8 +24 - 8+ k = 0`
` = -8`
APPEARS IN
संबंधित प्रश्न
Identify polynomials in the following:
`p(x)=2/3x^3-7/4x+9`
Identify constant, linear, quadratic and cubic polynomials from the following polynomials:
`r(x)=3x^2+4x^2+5x-7`
If `f(x) = 2x^2 - 13x^2 + 17x + 12` find f(2)
If `x = 2` is a root of the polynomial `f(x) = 2x2 – 3x + 7a` find the value of a.
In the following two polynomials, find the value of a, if x + a is a factor x3 + ax2 − 2x +a + 4.
What must be subtracted from x3 − 6x2 − 15x + 80 so that the result is exactly divisible by x2 + x − 12?
x3 + 2x2 − x − 2
If x − 3 is a factor of x2 − ax − 15, then a =
Factorise the following:
2a2 + 9a + 10
Factorise the following:
`sqrt(5)"a"^2 + 2"a" - 3sqrt(5)`
