Question

If x = 1, y = 2 and z = 3, find the value of x² + y² + 2xyz.

Answer 1

Given:
x =1
y = 2
z = 3

Substituting x = 1, y = 2 and z = 3 in the given equation (x² + y² + 2xyz):

\[\left( 1 \right)^2 + \left( 2 \right)^2 + 2\left( 1 \right)\left( 2 \right)\left( 3 \right)\]
\[ \Rightarrow 1 + 4 + 12 = 17\frac{}{}\]