Advertisements
Advertisements
प्रश्न
If (x – 1) divides the polynomial kx3 – 2x2 + 25x – 26 without remainder, then find the value of k
Advertisements
उत्तर
p(x) = kx3 – 2x2 + 25x – 26
When it is divided by x – 1
P(1) = 0
k(1)3 – 2(1)2 + 25(1) – 26 = 0
k – 2 + 25 – 26 = 0
k + 25 – 28 = 0
k – 3 = 0
k = 3
The value of k = 3
APPEARS IN
संबंधित प्रश्न
If (x + 2) and (x + 3) are factors of x3 + ax + b, find the values of ‘a’ and ‘b’.
If 2x + 1 is a factor of 2x2 + ax – 3, find the value of a.
If x + a is a common factor of expressions f(x) = x2 + px + q and g(x) = x2 + mx + n; show that : `a = (n - q)/(m - p)`
Prove by factor theorem that
(x-2) is a factor of 2x3- 7x -2
Prove by factor theorem that
(2x - 1) is a factor of 6x3 - x2 - 5x +2
Find the value of m ·when x3 + 3x2 -m x +4 is exactly divisible by (x-2)
Prove that ( p-q) is a factor of (q - r)3 + (r - p) 3
Show that (x – 3) is a factor of x3 – 7x2 + 15x – 9. Hence factorise x3 – 7x2 + 15 x – 9
Use factor theorem to factorise the following polynominals completely. x3 – 13x – 12.
If (2x – 3) is a factor of 6x2 + x + a, find the value of a. With this value of a, factorise the given expression.
