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If w(x, y) = xy + sin(xy), then Prove that ∂2w∂y∂x=∂2w∂x∂y - Mathematics

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प्रश्न

If w(x, y) = xy + sin(xy), then Prove that `(del^2w)/(delydelx) = (del^2w)/(delxdely)`

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उत्तर

w(x, y) = xy + sin(xy)

L.H.S = `(del^2w)/(delydelx)`

= `del/(dely) [(delw)/(delx)]`

= `del/(dely) [y + y cos (xy)]`

= `1 + y[ x sin (xy)]`

= `1 - xy sin (xy)`  .......(1)

R.H.S =`(del^2w)/(delxdely)`

= `del/(delx) [(delw)/(dely)]`

From (1) and (2)

⇒ `(del^2w)/(delydelx) = (del^2w)/(delxdely)`

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Partial Derivatives
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 8: Differentials and Partial Derivatives - Exercise 8.4 [पृष्ठ ७९]

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सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
पाठ 8 Differentials and Partial Derivatives
Exercise 8.4 | Q 8 | पृष्ठ ७९

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