Advertisements
Advertisements
प्रश्न
If the temperature and pressure of a gas is doubled the mean free path of the gas molecules ____________.
पर्याय
remains same
doubled
tripled
quadrapoled
Advertisements
उत्तर
If the temperature and pressure of a gas is doubled the mean free path of the gas molecules remains same.
APPEARS IN
संबंधित प्रश्न
Estimate the mean free path and collision frequency of a nitrogen molecule in a cylinder containing nitrogen at 2.0 atm and temperature 17 °C. Take the radius of a nitrogen molecule to be roughly 1.0 Å. Compare the collision time with the time the molecule moves freely between two successive collisions (Molecular mass of N2 = 28.0 u).
Choose the correct option.
The mean free path λ of molecules is given by where n is the number of molecules per unit volume and d is the diameter of the molecules.
Define mean free path and write down its expression.
List the factors affecting the mean free path.
What is the reason for the Brownian motion?
Derive the expression for the mean free path of the gas.
Calculate the mean free path of air molecules at STP. The diameter of N2 and O2 is about 3 × 10−10 m
Consider an ideal gas at pressure P, volume V and temperature T. The mean free path for molecules of the gas is L. If the radius of gas molecules, as well as pressure, volume and temperature of the gas are doubled, then the mean free path will be:
Mean free path of molecules of a gas is inversely proportional to ______.
Calculate the ratio of the mean free paths of the molecules of two gases having molecular diameters 1 A and 2 A. The gases may be considered under identical conditions of temperature, pressure and volume.
