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प्रश्न
If the tangent to the curve y = x3 at the point P(t, t3) meets the curve again at Q, then the ordinate of the point which divides PQ internally in the ratio 1:2 is ______.
पर्याय
–2t3
–t3
0
2t3
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उत्तर
If the tangent to the curve y = x3 at the point P(t, t3) meets the curve again at Q, then the ordinate of the point which divides PQ internally in the ratio 1:2 is `underlinebb(-2"t"^3)`.
Explanation:
Given: Tangent to the curve y = x3 at the point
P(t, t3) meets the curve again at Q
Curve is y = x3 ...(i)
Differentiate both sides w.r.t.x
`("dy")/("d"x)` = 3x2
⇒ `|("dy")/("d"x)|_(("t""," "t"^3))` = 3t2 = Slope of tangent at P
Equation of straight line having slope m and passing through (x1, x1) is y – y1 = m(x – x1)
Here, m = 3t2, (x1, y1) = (t, t3)
∴ Equation of tangent at P(t, t3) is
(y – t3) = 3t2(x – t) ...(ii)
Putting value of y from equation (i), we get
x3 – t3 = 3t2(x – t)
⇒ x2 + xt + t2 = 3t2
⇒ x2 + xt – 2t2 = 0
⇒ (x – t)(x + 2t) = 0
⇒ x1 = t, x2 = –2t,
From, y = x3
y1 = t3, y2 = –8t3
∴ Point Q is (–2t, –8t3).
Use section formula, to find R which divides PQ internally in the ratio 1:2
∴ R = `((1 xx (-2"t") + 2"t")/(1 + 2), (1 xx (-8"t"^3) + 2"t"^3)/(1 + 2))` ≡ (0, –2t3)
So, the coordinate of required point is –2t3.
