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प्रश्न
If the tangent at (1, 7) to the curve x2 = y – 6 touches the circle x2 + y2 + 16x + 12y + c = 0 then the value of c is ______.
पर्याय
185
85
95
195
MCQ
रिकाम्या जागा भरा
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उत्तर
If the tangent at (1, 7) to the curve x2 = y – 6 touches the circle x2 + y2 + 16x + 12y + c = 0 then the value of c is 95.
Explanation:
Equation of tangent at (1, 7) to x2 = y – 6 is 2x – y + 5 = 0.

Now, perpendicular from centre O(–8, –6) to 2x – y + 5 = 0 should be equal to radius of the circle
∴ `|(-16 + 6 + 5)/sqrt(5)| = sqrt(64 + 36 - C)`
`\implies sqrt(5) = sqrt(100 - c)`
`\implies` c = 95
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Application of Derivative in Geometry
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