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प्रश्न
If the sum of squares of differences of ranks for 10 pairs of observations is 66, find the rank correlation coefficient.
बेरीज
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उत्तर
Given n = 10, ∑d2 = 66
We have R = 1 - `[ 6∑d^2 ]/[ n( n^2 - 1 )]`
= 1 - ` [ 6 xx 66 ]/[ 10 ( 10^2 - 1 )]`
= 1 - `396/990` = 1 - 0.4 = 0.6
∴ R = 0.6
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