Question

If the standard electrode potential of Cu²⁺/Cu electrode is 0.34 V, what is the electrode potential if concentration of Cu²⁺ ions is 0.01 M (T = 298 K)?

पर्याय

• 0.39 V

• 0.28 V

• 0.22 V

• 0.17 V

Answer 1

0.28 V

Explanation:

`"E"_((Cu^(2+)//Cu))` = `"E"_((Cu^(2+)//Cu))^0 - 0.0592/"n" log  1/(["Cu"^(2+)])`

= `0.34 - 0.0592/2 log  1/0.01`

= 0.3400 − 0.0592

= 0.2808 V