Question

If the prime factorisation of a natural number n is 2⁴ × 3⁴ × 5³ × 7, then the number of consecutive zeros in n, is ______.

Answer 1

If the prime factorisation of a natural number n is 2⁴ × 3⁴ × 5³ × 7, then the number of consecutive zeros in n, is 3.

Explanation:

Each trailing zero needs a factor 10 = 2 × 5.

So the count is min(v2, v5) = min(4, 3) = 3.