Question

If the median of 33, 28, 20, 25, 34, x is 29, find the maximum possible value of x.

Answer 1

There are 6 observations i.e. even no. of observations.

So, median will be:

`(("3rd observation + 4th observation"))/2`

Arranging in increasing order:

20, 25, 28, x, 33, 34

If we put any other number at 4th position the n, we will not get the median = 29

So, `(28 + x)/2` = 29

28 + x = 58

x = 58 − 28

= 30