मराठी

If the mean of the data given in adjoining table is 20 , the relation between x1 and x2 is: x 10 20 30 f x_1 20 x_2

Advertisements
Advertisements

प्रश्न

If the mean of the data given in adjoining table is 20, the relation between x1 and x2 is:

x f
10 x1
20 20
30 x2

पर्याय

  • x1 + x2 = 30

  • x1 − x2 = 15

  • x1 − x2 = 0

  • x1 + x2 = 20

MCQ
Advertisements

उत्तर

x1 − x2 = 0

Explanation:

x f fx
10 x1 10x1
20 20 400
30 x2 30x2
Total Σf = 20 + x1 + x2 Σfx = 400 + 10x1 + 30x2

By formula,

\[\text{Mean} = \frac{\Sigma fx}{\Sigma f}\]

Substituting values we get:

\[\Rightarrow 20 = \frac{400 + 10x_1 + 30x_2}{20 + x_1 + x_2}\]

\[\Rightarrow 20(20 + x_1 + x_2) = 400 + 10x_1 + 30x_2\]

\[\Rightarrow 400 + 20x_1 + 20x_2 = 400 + 10x_1 + 30x_2\]

\[\Rightarrow 20x_1 - 10x_1 + 20x_2 - 30x_2 = 400 - 400\]

\[\Rightarrow 10x_1 - 10x_2 = 0\]

\[\Rightarrow 10(x_1 - x_2) = 0\]

\[\Rightarrow x_1 - x_2 = 0.\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 24: Measure of Central Tendency (Mean, Median, Quartiles and Mode) - EXERCISE 24 (B) [पृष्ठ ३७५]

APPEARS IN

सेलिना Concise Mathematics [English] Class 10 ICSE
पाठ 24 Measure of Central Tendency (Mean, Median, Quartiles and Mode)
EXERCISE 24 (B) | Q 1. (d) | पृष्ठ ३७५
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×