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प्रश्न
If the mean of the data given in adjoining table is 20, the relation between x1 and x2 is:
| x | f |
| 10 | x1 |
| 20 | 20 |
| 30 | x2 |
पर्याय
x1 + x2 = 30
x1 − x2 = 15
x1 − x2 = 0
x1 + x2 = 20
MCQ
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उत्तर
x1 − x2 = 0
Explanation:
| x | f | fx |
| 10 | x1 | 10x1 |
| 20 | 20 | 400 |
| 30 | x2 | 30x2 |
| Total | Σf = 20 + x1 + x2 | Σfx = 400 + 10x1 + 30x2 |
By formula,
\[\text{Mean} = \frac{\Sigma fx}{\Sigma f}\]
Substituting values we get:
\[\Rightarrow 20 = \frac{400 + 10x_1 + 30x_2}{20 + x_1 + x_2}\]
\[\Rightarrow 20(20 + x_1 + x_2) = 400 + 10x_1 + 30x_2\]
\[\Rightarrow 400 + 20x_1 + 20x_2 = 400 + 10x_1 + 30x_2\]
\[\Rightarrow 20x_1 - 10x_1 + 20x_2 - 30x_2 = 400 - 400\]
\[\Rightarrow 10x_1 - 10x_2 = 0\]
\[\Rightarrow 10(x_1 - x_2) = 0\]
\[\Rightarrow x_1 - x_2 = 0.\]
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