Advertisements
Advertisements
प्रश्न
If the marginal revenue function is R'(x) = 1500 – 4x – 3x2. Find the revenue function and average revenue function
Advertisements
उत्तर
Given marginal revenue function
MR = R’(x)= 1500 – 4x – 3x2
Revenue function R(x) = `int "R'"(x) "d"x + "c"`
R = `int (1500 - 4x - 3x^2) "d"x + "c"`
R = 1500x – 2x2 – x3 + c
When x = 0
R = 0
⇒ c = 0
So R = 1500x – 2x2 – x3
Average revenue function P = `"R"/x` ⇒ 1500 – 2x – x2
APPEARS IN
संबंधित प्रश्न
An account fetches interest at the rate of 5% per annum compounded continuously. An individual deposits ₹ 1,000 each year in his account. How much will be in the account after 5 years. (e0.25 = 1.284)
If the marginal cost function of x units of output is `"a"/sqrt("a"x + "b")` and if the cost of output is zero. Find the total cost as a function of x
The demand equation for a products is x = `sqrt(100 - "p")` and the supply equation is x = `"P"/2 - 10`. Determine the consumer’s surplus and producer’s surplus, under market equilibrium
Find the consumer’s surplus and producer’s surplus for the demand function pd = 25 – 3x and supply function ps = 5 + 2x
Choose the correct alternative:
The profit of a function p(x) is maximum when
Choose the correct alternative:
The marginal cost function is MC = `100sqrt(x)`. find AC given that TC = 0 when the output is zero is
Choose the correct alternative:
The demand and supply function of a commodity are D(x) = 25 – 2x and S(x) = `(10 + x)/4` then the equilibrium price p0 is
Choose the correct alternative:
For a demand function p, if `int "dp"/"p" = "k" int ("d"x)/x` then k is equal to
The marginal revenue function for a firm given by MR = `2/(x + 3) - (2x)/(x + 3)^2 + 5`. Show that the demand function is P = `(2x)/(x + 3)^2 + 5`
The demand equation for a product is Pd = 20 – 5x and the supply equation is Ps = 4x + 8. Determine the consumers surplus and producer’s surplus under market equilibrium
