Question

If the equation, x² – ax + 1 = 0 has two distinct and real roots, then:

पर्याय

• |a| ≥ 2

• |a| ≤ 2

• |a| > 2

• |a| < 2

Answer 1

|a| > 2

Explanation:

For two distinct real roots the discriminant must be > 0.

Here, b = –a and c = 1.

So, D = b² – 4ac = a² – 4. 

Thus, a² – 4 > 0

⇒ a² > 4

⇒ |a| > 2