मराठी

If the equation x^2 + 5kx + 16 = 0 has no real roots, then:

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प्रश्न

If the equation x2 + 5kx + 16 = 0 has no real roots, then:

पर्याय

  • `k > 8/5`

  • `k < -8/5`

  • `-8/5 < k < 8/5`

  • none of these

MCQ
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उत्तर

`bb(-8/5 < k < 8/5)`

Explanation:

Comparing x2 + 5kx + 16 = 0 with ax2 + bx + c = 0 we get,

a = 1, b = 5k and c = 16.

We know that,

Since equations has no real roots,

⇒ D < 0

⇒ b2 – 4ac < 0

⇒ (5k)2 – 4(1)(16) < 0

⇒ 25k2 – 64 < 0

⇒ 25k2 < 64

⇒ `k^2 < 64/25`

⇒ `|k| < sqrt(64/25)`

⇒ `|k| < 8/5`

⇒ `-8/5 < k < 8/5`

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पाठ 5: Quadratic Equation - EXERCISE 5C [पृष्ठ ६३]

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आर. एस. अग्रवाल Mathematics [English] Class 10 ICSE
पाठ 5 Quadratic Equation
EXERCISE 5C | Q 27. | पृष्ठ ६३
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