Question

If the enthalpy change for the transition of liquid water to steam is 300 kJ mol^–1 at 27°C, the entropy change for the process would be:

पर्याय

• 1000 JK^–1 mol^–1 

• 10 JK^–1 mol^–1 

• 1 JK^–1 mol^–1 

• 0.1 JK^–1 mol^–1 

Answer 1

1000 JK^–1 mol^–1 

Explanation:

ΔS_vap = `(ΔH_(vap))/T = (300 kJ  mol^-1)/(300 k)`

= 1000 JK^–1 mol^–1