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प्रश्न
If the corner points of the feasible solution are (0, 10), (2, 2) and (4, 0), then the point of minimum z = 3x + 2y is ______.
पर्याय
(2, 2)
(2, 2)
(0, 10)
(0, 10)
(4, 0)
(4, 0)
(3, 4)
(2, 4)
MCQ
रिकाम्या जागा भरा
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उत्तर
If the corner points of the feasible solution are (0, 10), (2, 2) and (4, 0), then the point of minimum z = 3x + 2y is (2, 2).
Explanation:
Z = 3x + 2y
At (0, 10) = Z = 0 + 2 (10) = 20
At (2, 2), = Z = 3 (2) + 2 (2) = 10
At (4, 0), Z = 3 (4) + 0 = 12
The minimum value of Z is 10 and it occurs at (2, 2).
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Notes
The answer in the textbook is incorrect.
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