Question

If the corner points of the feasible region are (0, 10), (2, 2) and (4, 0) then the point of minimum z  = 3x + 2y is ______.

पर्याय

• (2, 2)

• (0, 10)

• (4, 0)

• (2, 4)

Answer 1

If the corner points of the feasible region are (0, 10), (2, 2) and (4, 0) then the point of minimum z  = 3x + 2y is (2, 2).

Explanation:

We are given corner points: 

(0, 10), (2, 2), (4, 0)

Objective function:

z = 3x + 2y

Now calculate z at each point:

At (0, 10)

z = 3(0) + 2(10) = 20

At (2,2):

z = 3(2) + 2(2) = 6 + 4 = 10

At (4, 0):

z = 3(4) + 2(0) = 12

The minimum value is 10 at the point (2, 2).