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प्रश्न
If \[\text{I}=\int e^{-x}\cos x\,dx\], which relation is obtained during integration by parts?
पर्याय
\[2\text{I}=(\sin x+\cos x)e^{-x}\]
\[2\text{I}=(\cos x-\sin x)e^{x}\]
\[\text{I}=(\sin x-\cos x)e^{-x}\]
\[2\text{I}=(\sin x-\cos x)e^{-x}\]
MCQ
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उत्तर
Integration by parts returns the original integral \[\text{I}\] to the right-hand side. Collecting it gives \[2\text{I}=(\sin x-\cos x)e^{-x}\].
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