मराठी

If Tan a = 1 − Cos B Sin B , Then Find the Value of Tan2a.

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प्रश्न

If \[\text{ tan } A = \frac{1 - \text{ cos } B}{\text{ sin } B}\]

, then find the value of tan2A.

 

 

टीपा लिहा
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उत्तर

Given:

\[\text{ tan } A = \frac{1 - \text{ cos } B}{\text{ sin } B}\]

\[ \Rightarrow \text{ tan } A = \frac{2 \sin^2 \frac{B}{2}}{2\sin\frac{B}{2}\cos\frac{B}{2}} \left( 1 - \cos2\theta = 2 \sin^2 \theta \text{ and }  \sin2\theta = 2\sin\theta\cos\theta \right)\]

\[ \Rightarrow \text{ tan } A = \frac{\sin\frac{B}{2}}{\cos\frac{B}{2}} = \tan\frac{B}{2}\]

\[ \Rightarrow A = \frac{B}{2}\]

\[\Rightarrow 2A = B\]
\[ \therefore \tan2A = \text{ tan } B\]

Hence, the value of tan2is tanB.

 
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Values of Trigonometric Functions at Multiples and Submultiples of an Angle
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पाठ 9: Values of Trigonometric function at multiples and submultiples of an angle - Exercise 9.4 [पृष्ठ ४२]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 9 Values of Trigonometric function at multiples and submultiples of an angle
Exercise 9.4 | Q 11 | पृष्ठ ४२

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