Advertisements
Advertisements
प्रश्न
If `sin (A - B) = cos (A + B) = 1/2`, find A and B.
बेरीज
Advertisements
उत्तर
Step 1: Formulate the equations
From trigonometric standard values, we identify the angles that result in a value of `1/2` for both sine and cosine functions:
Since `sin 30^circ = 1/2`, the first equation is:
A – B = 30° ...(i)
Since `cos 60^circ = 1/2`, the second equation is:
A + B = 60° ...(ii)
Step 2: Solve the linear system
We can find the values of A and B by solving these two simultaneous equations:
1. Add equations (i) and (ii):
(A – B) + (A + B) = 30° + 60°
2A = 90°
A = 45°
2. Substitute A = 45° into equation (ii):
45° + B = 60°
B = 60° – 45°
B = 15°
Verification
sin (45° – 15°) = sin 30°
= `1/2`
cos (45° + 15°) = cos 60°
= `1/2`
The values are A = 45° and B = 15°.
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
