Question

If sin A = `9/41` find all the values of cos A and tan A

Answer 1

We have sin A = `9/41`
As,
`Cos^2 A= 1 − sin^2 A`

=`1-(9/41)^2`

=`1-81/1681`

=`(1681-81)/1681`

`⇒ cos^2 A = 1600/1681`

`⇒ cos A = sqrt(1600/1681)`

`⇒ cos A = 40/41`

Also, 

`Tan A = sin A/cos A`

`= ((9/41))/((40/41))` 

`=9/40`